• Zwuzelmaus@feddit.org
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    6 days ago

    Why should it squirt out? Who would want that? Think about basics:

    Pressure is force divided by area.

    The weight of the ball (downward force) equals the upward force from the water pressure, then it can float.

    You want the water pressure to be about 1 bar (equal the air), so it does not squirt out.

    From that you get: weight of the ball divided by the partial area of the ball that is in the water equals 1 bar.

    That’s how big and how heavy your ball must be, then it works.

    • Karmanopoly@lemmy.worldOP
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      6 days ago

      It’s not floating though

      It’s more like hydroplaning

      At some point the weight of the ball would close off the water and force it out like squirting

      • prole@lemmy.blahaj.zone
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        5 days ago

        It’s more like hydroplaning

        You mean the thing that, in this very thread, you were arguing does not exist?

        What are you even doing? Seriously.

      • MentalEdge@sopuli.xyz
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        6 days ago

        The water comes out at a single point at high pressure below the sphere.

        It then travels out and exits all around the sphere.

        The water can be pumped below the sphere very slowly, but at high pressure, and that way still lift the sphere.

        The water doesn’t get squeezed and accelerate towards the outside edge, because as it flows outward, the circle gets bigger. The area expands.

        Hence it slows down, drops in pressure, and comes out at a trickle.

        It’s not like pinching the end of a hose. It’s like adding a kink in the hose before the end. There is huge pressure before the kink (that water tha lifts the sphere), and after the kink the pressure is super low (the water exiting from below the sphere). It makes the water slow down and come out at a trickle. Even though the pressure before the kink is huge.