Call me Lenny/Leni@lemm.eeM to Ask Lemmy@lemmy.worldEnglish · 10 hours agoWhat's the wrongest thing a teacher ever told you?message-squaremessage-square95fedilinkarrow-up11arrow-down10
arrow-up11arrow-down1message-squareWhat's the wrongest thing a teacher ever told you?Call me Lenny/Leni@lemm.eeM to Ask Lemmy@lemmy.worldEnglish · 10 hours agomessage-square95fedilink
minus-squaresafesyrup@feddit.orglinkfedilinkEnglisharrow-up0·8 hours agoThat x^0.5 is not the same as the square root of x
minus-squaresartalon@lemmy.worldlinkfedilinkarrow-up0·5 hours agoX^3 = x•x•x X^2 = x•x X^1 = x X^0 = 1 X^-1 = 1/x X^-2 = 1/(x•x) X^-3 = 1/(x•x•x) When the exponent is between -1 and 1, it becomes a root function: X^(1/2) = sqrt(x) X^(1/3) = cubic root(x) X^-(1/2) = 1/(sqrt(x)) X^-(1/3) = 1/(cubic root(x))
minus-squareJPAKx4@lemmy.blahaj.zonelinkfedilinkarrow-up0·3 hours agoOh I misunderstood the original comment, the teacher said it wasn’t the same, but it is the same. My understanding is that sqrt(x) = x^1/2
That x^0.5 is not the same as the square root of x
Please explain :)
X^3 = x•x•x
X^2 = x•x
X^1 = x
X^0 = 1
X^-1 = 1/x
X^-2 = 1/(x•x)
X^-3 = 1/(x•x•x)
When the exponent is between -1 and 1, it becomes a root function:
X^(1/2) = sqrt(x)
X^(1/3) = cubic root(x)
X^-(1/2) = 1/(sqrt(x))
X^-(1/3) = 1/(cubic root(x))
Oh I misunderstood the original comment, the teacher said it wasn’t the same, but it is the same. My understanding is that sqrt(x) = x^1/2